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1 year ago

An extraneous solution IS a(n)

Mathematics

1 answer:

max2010maxim [7]1 year ago

4 0

Answer:

See below

Step-by-step explanation:

An invalid solution.

When you use the quadratic formula, for example, to solve for 't', time, you will often find one of the values of 't' to be NEGATIVE value for time.....this would be an extraneous solution.

Sometimes when working with LOG equations you may fin an answer which is negative.....you cannot have a LOG of a negative number...THAT solution would be EXTRANEOUS

ETC

SO, always check your answers to see if they 'work' for your problem.

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Given the information in the picture, which trigonometric identity can be used to solve for the height of the blue ladder that i

Stells [14]

The trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is $\rm sin=\dfrac{o}{h}$ .

We have to determine

Which trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building?.

<h3>Trigonometric identity</h3>

Trigonometric Identities are the equalities that involve trigonometry functions and hold true for all the values of variables given in the equation.

Trig ratios help us calculate side lengths and interior angles of right triangles:

The trigonometric identity that can be used to solve for the height of the blue ladder is;

$\rm Sin47=\dfrac{50}{H}\\\\H=\dfrac{50}{sin47}\\\\H=68 feet$

Hence, the trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is $\rm sin=\dfrac{o}{h}$ .

To know more about trigonometric identity click the link given below.

brainly.com/question/1256744

6 0

2 years ago

Whats the answer plz

elena-14-01-66 [18.8K]

Answer:

The correct answer should be A not 100% sure

4 0

2 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago

Find the domain of the graphed function?

MariettaO [177]

Remember, the domain of a function is all of the x values in the (x,y) coordinates. For this, let’s take a few bench mark coordinates. (0,0) (1,2.5)(2,0) (3, -9). Those definitely aren’t all real numbers, so eliminate A. X is not only less than or equal to 0, so eliminate C.

It’s B.

7 0

3 years ago

Read 2 more answers

Find the length of BC. A.) 14 B.) 9 C.) 2 D.) 3

Vera_Pavlovna [14]

Answer:

A) 14

Step-by-step explanation:

BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.

3y+5=5y-1

subtract 3y from both sides --> 5=2y-1

add 1 to both sides --> 6=2y

now get y alone, divide by 2 by both side --> y=3

plug y in back to 5y-1 --> 5x3-1

15-1

BC = 14

7 0

3 years ago