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vodomira [7]
4 years ago
9

Which source is most likely an authority on the subject

Chemistry
2 answers:
german4 years ago
7 0
Please put the answers!
cestrela7 [59]4 years ago
4 0

Answer:

Dr. Patel, a cardiologist, presents her findings on heart disease

Explanation:

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Is c2h2 polar or non polar?
Lyrx [107]

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polar beacuse there is no way its non polar.

3 0
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inysia [295]

Ocean currents act much like a conveyor belt, transporting warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Thus, ocean currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface. I think its B

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what is the correct conversion factor by to which to multiply to convert moles of hyrdogen peroxide (H2O2) to moles of oxygen (O
raketka [301]

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I looked it up I think I got it but idk

5 0
3 years ago
If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
Write the equilibrium constant: Pb3(PO4)2(s) = 3Pb2+ (aq) +<br> 2PO2 (aq)
kicyunya [14]

Answer:

Kc = [Pb²⁺]³.[PO₄³⁻]²

Explanation:

Let's consider the following reaction at equilibrium.

Pb₃(PO₄)₂(s) ⇄ 3 Pb²⁺(aq) + 2 PO₄³⁻(aq)

The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [Pb²⁺]³.[PO₄³⁻]²

This equilibrium constant is known as the solubility product of Pb₃(PO₄)₂.

7 0
3 years ago
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