The description below proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
<h3>How to prove an Isosceles Triangle?</h3>
Let ABC be an isosceles triangle such that AB = AC.
Let AD be the bisector of ∠A.
We want to prove that BD=DC
In △ABD & △ACD
AB = AC(Thus, △ABC is an isosceles triangle)
∠BAD =∠CAD(Because AD is the bisector of ∠A)
AD = AD(Common sides)
By SAS Congruency, we have;
△ABD ≅ △ACD
By corresponding parts of congruent triangles, we can say that; BD=DC
Thus, this proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
Read more about Isosceles Triangle at; brainly.com/question/1475130
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Answer: -5
Step-by-step explanation: -2 -3 = -5
I think the answer is B that what i think
Answer:
2x³ + 5x² - 12x
Step-by-step explanation:
The correct answer doesn't seem to be listed...
(fg)(x) = (2x² - 3x)(x + 4)
Which equals...
2x²(x) + 2x²(4) + (-3x)(x) + (-3x)(4)
Which simplifies to...
2x³ + 8x² - 3x² - 12x
2x³ + 5x² - 12x
Answer:
- x ≥ 15, interval notation x ∈ [15, +∞)
- x < 10, interval notation x ∈ (-∞, 10)
<u>Combined together:</u>