Answer:
A) Does not change
B) Decrease
C) Increasing
D) Increasing
Explanation:
When it pushes it's volume is reduced by 1/3 because it's Area is constant there for only volume is decreased. Then the number of molecules don't change
A) don,t change
B) Decreases
C) Density is increased because it mass doesn't change. there for
Mass = Density * Volume
When Volume is decreasing to keep mass constant Density will be increased.
D) Pressure is increased according to the boil's law. it says that for fixed mass and fixed temperature pressure is inversely proportional to the volume. then volume decrease pressure increase
Answer:
Steam-methane reforming
Electrolysis of water
Explanation:
Steam methane reforming involves reaction of methane with water in the presence of a catalyst such as nickel to form Carbon oxides and Hydrogen.
CH4 + H2O ⇌ CO + 3 H
Electrolysis of water involves splitting of water through application of electric current to give Hydrogen and Oxygen gas.
2 H2O(l) → 2 H2(g) + O2(g)
Answer:
D is the correct answer! Hope this helps you!!!!
Explanation:
The formula for solving voltage is V=IR where V represents the voltage, where "I" represent the current and R represents the resistance. Then, the given values are enumerated below and these will help us in solving for the unknown.
V=10 volts
I=?
R=2 ohms
V=IR
I=V/R
I=10/2
I=5 amperes
Therefore, the current is 5 amperes.
The shot putter should get out of the way before the ball returns to the launch position.
Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.
The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 = 0.45 s
t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.
Answer: 0.45 s
