Answer:
5773.50269 Hz
23 A
Explanation:
= Inductance = 6 mH
= Capacitance = 5 μF
= Resistance = 3 Ω
= Maximum emf = 69 V
Resonant angular frequency is given by
![\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D%5C%5C%5CRightarrow%20%5Comega%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7B6%5Ctimes%2010%5E%7B-3%7D%5Ctimes%205%5Ctimes%2010%5E%7B-6%7D%7D%7D%5C%5C%5CRightarrow%20%5Comega%3D5773.50269%5C%20Hz)
The resonant angular frequency is 5773.50269 Hz
Current is given by
![I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B%5Cepsilon%7D%7BR%7D%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B69%7D%7B3%7D%5C%5C%5CRightarrow%20I%3D23%5C%20A)
The current amplitude at the resonant angular frequency is 23 A
Answer
Around 400 B.C.E, the Greek philosopher Democritus introduced the idea of the atom as the basic building block matter. Democritus though that atoms are tiny, uncuttable, solid particles that are surrounded by empty space and constantly moving at random.
Pls give me BRAINLIEST
0.04m²
Explanation:
Given parameters:
Pressure = 250000Pa
Weight = 40000N
Unknown:
Area of each foot = ?
Solution:
Pressure is the force exerted per unit area of a body
Pressure = ![\frac{force}{area}](https://tex.z-dn.net/?f=%5Cfrac%7Bforce%7D%7Barea%7D)
To find the area;
Area = ![\frac{force }{pressure}](https://tex.z-dn.net/?f=%5Cfrac%7Bforce%20%7D%7Bpressure%7D)
Area =
= 0.16m²
The force exerted by all the four feet is 0.16m²
the area of each feet =
= 0.04m²
Learn more:
Pressure brainly.com/question/7139767
#learnwithBrainly
Answer:
Frequency, ![f=2.18\times 10^9\ Hz](https://tex.z-dn.net/?f=f%3D2.18%5Ctimes%2010%5E9%5C%20Hz)
Explanation:
We have,
Speed of radio waves is ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
Wavelength of radio waves is ![\lambda=0.137\ m](https://tex.z-dn.net/?f=%5Clambda%3D0.137%5C%20m)
It is required to find the frequency of the radio waves. The speed of a wave is given by :
![v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.137}\\\\f=2.18\times 10^9\ Hz](https://tex.z-dn.net/?f=v%3Df%5Clambda%5C%5C%5C%5Cf%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D%5C%5C%5C%5Cf%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B0.137%7D%5C%5C%5C%5Cf%3D2.18%5Ctimes%2010%5E9%5C%20Hz)
So, the frequency of the radio wave is
.
Answer:
0.12 K
Explanation:
height, h = 51 m
let the mass of water is m.
Specific heat of water, c = 4190 J/kg K
According to the transformation of energy
Potential energy of water = thermal energy of water
m x g x h = m x c x ΔT
Where, ΔT is the rise in temperature
g x h = c x ΔT
9.8 x 51 = 4190 x ΔT
ΔT = 0.12 K
Thus, the rise in temperature is 0.12 K.