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klemol [59]
2 years ago
11

1. What is the name given to the total possibility of sound frequencies

Physics
1 answer:
exis [7]2 years ago
4 0

Explanation:

1. The entire span of possible sound waves is called the acoustic spectrum. It is subdivided into infrasonic sounds, audible sounds, and ultrasonic sounds.

2. The difference between a musical note and another note at twice the frequency is called an octave.

3. Sound intensity varies with the inverse square of distance.

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What s physics?
Alex777 [14]

The answer is (B. The study of Matter and Energy) but technically you could consider physics all of these as engineering is based on physics and that would be the study of inventions, chemistry and biology were both discovered because of physics, and physics invokes more math than any other subject as it applies math to the entire Universe.

7 0
3 years ago
Read 2 more answers
If you and a friend are standing at opposites ends of a gymnasium and one of you claps, will the other hear the clap at the same
34kurt

Answer:

No. Your friend will not hear the clap when he/she sees it.

Explanation:

It takes time for sound waves to go through a large area. It takes longer if people are in the area rather than it is empty.

3 0
3 years ago
1. What is the potential energy of a 5.0-kg
babymother [125]

Answer:

  C.  98 J

Explanation:

The appropriate formula is ...

  PE = mgh . . . . . m is mass; below, m is meters

  PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2

  PE = 98 J

5 0
3 years ago
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai
taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

v=f_1\lambda_1

Wavelength for f = 45 Hz is,

\lambda_1=\dfrac{v}{f_1}

\lambda_1=\dfrac{343}{45}=7.62\ m

Wavelength for f = 375 Hz is,

\lambda_2=\dfrac{v}{f_2}

\lambda_2=\dfrac{343}{375}=0.914\ m/s

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

6 0
3 years ago
Cognitive maps allow organisms to
RoseWind [281]
B. Mentally represent their environment
5 0
3 years ago
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