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Assoli18 [71]
3 years ago
6

Brianna weighs 425 N. She climbs a flight of stairs to a height of 8 m. It takes her 6 seconds.

Physics
1 answer:
Aleks [24]3 years ago
5 0
<span>So we want to know how much work does Brianna do while climbing the stairs to a height h=8m while she weighs F=425N and in t=6s. So work W is defined as Force F times distance h or: W=F*h. Since Brianna has to use the force that is equal to her own weight during her climbing the calculation is this: W=F*h=425N * 8m=3400J. The work she does is W=3400 J.</span>
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Explanation:

Given:

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  • time duration of the first interval, t_1=2.9\ s
  • distance down the field in the second interval, d_2=-2.5\ m
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a)

velocity in the first interval:

v_1=\frac{d_1}{t_1}

v_1=\frac{16}{2.9}

v_1=5.5172\ m.s^{-1}

b)

velocity in the second interval:

v_2=\frac{d_2}{t_2}

v_2=\frac{-2.5}{1.65}

v_2=-1.5152\ m.s^{-1}

c)

velocity in the third interval:

v_3=\frac{d_3}{t_3}

v_3=\frac{24}{5.2}

v_3=4.6154\ m.s^{-1}

d)

We know that the average velocity is given as the total displacement per unit time.

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v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}

v_{avg}=3.8462\ m.s^{-1}

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