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LekaFEV [45]
3 years ago
9

Calculate the kinetic energy of a 8 kg object moving at a velocity of 4 m/s.

Physics
2 answers:
Tanya [424]3 years ago
5 0

the answer to your question is 200 J

GarryVolchara [31]3 years ago
4 0

Answer:

<h2>64 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 8 \times  {4}^{2}   \\  = 4 \times 16

We have the final answer as

<h3>64 J</h3>

Hope this helps you

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Answer:

The value  is   a =  2.7183

Explanation:

From the question we are told that

   The  relationship between the number of whooping cranes and the number of decades is ln N =  2.85 + 0.039t

  The  exponential relationship is  N  =  na^{kt}

Now from the given equation we have that

       N  =   e^{2.85 + 0.039t}

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So comparing this equation obtained an the given  exponential relationship we have that

      n = 17.29

       k  =  0.039

        a =  e =  2.7183

        a =  2.7183

 

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Which of the following is known as the following cycle because it's reservoir is a rock.
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A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
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7 0
3 years ago
Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe
Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * 10^{6} m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × 10^{-19} C

mass of electron  = 9.1 × 10^{-31} kg

Force in an electric field = q*E

potential energy is stored in the form of work done

potential energy = work done = Force * displacement

                                                   = q * (E * d)  

                                                   = q * (V) = 1.6 × 10^{-19} * 100

stored potential energy = kinetic energy in electric field

kinetic energy = 1/2 * m * v^{2}

                        = 1/2 *  9.1 × 10^{-31} *  v^{2}

equation both the equations

1/2 *  9.1 × 10^{-31} *  v^{2} = 1.6 × 10^{-17}

v^{2} = 0.352 * 10^{14} m/s

v^{2} = 35.2 * 10^{12}

    = 5.93 * 10^{6} m/s

To learn more about  kinetic energy in electric field  here

brainly.com/question/8666051

#SPJ4

3 0
1 year ago
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