Answer:
The Fermi energy is 0.568 eV and the conductivity at room temperature is 31.24 (Ωcm)⁻¹
Explanation:
Data given:
Nd = doping concentration = 5x10⁶/cm³
According the mass action law, the hole concentration is:



The conductivity of n-type of semi-conductor is equal to:
The mobility of Germanium is 3900 cm²/Vs
σ = 1.6x10⁻¹⁹ * 5x10¹⁶ * 3900 = 31.24 (Ωcm)⁻¹
Answer:
a) 
b) 
c) 
Explanation:
Before the wire is inserted, the total charge on the inner and outer surface of the cylindrical shell is as follows:


Here, 'h' denotes the length of the cylinder. The total charge of the cylindrical shell is -0.395h μC.
When the thin wire is inserted, the positive charge of the wire attracts the same amount of negative charge on the inner surface of the shell.

a) The new charge on the inner shell is -1.1h μC. Therefore, the new surface charge density of the inner shell can be calculated as follows:

b) The new charge on the outer shell is equal to the total charge minus the inner charge. Therefore, the new charge on the outer shell is +0.705 μC.
The new surface charge density can be calculated as follows:

c) The electric field outside the cylinder can be found by Gauss' Law:

We will draw an imaginary cylindrical shell with radius r > r2. The integral in the left-hand side will be equal to the area of the imaginary surface multiplied by the E-field.

Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.
The surprising thing was that quasars and active galaxies have a lot of mass in the center of the very small volume of the space.
Therefore, the surprising thing about quasars was that due to this mass and energy they are 100 times more luminous than Milky Way which means they have high recession velocity and a very large amount of red-shifting.
To learn more about quasars, refer: brainly.com/question/9965257
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So, all Turkeys work to attract female Turkeys, but only dominant Turkeys benefit from it, and the less dominant Turkeys don't benefit at all from it. That means that they are exhibiting altruism:selfless behavior.
However, in practical terms their behaviour also helps them, as they are often related to the dominant males.
Answer:
6.1 m/s
Explanation:
Take up to be positive. Given (in the y direction):
Δy = 1.4 m
vᵧ = 0 m/s
g = -10 m/s²
Find: v₀ᵧ
vᵧ² = v₀ᵧ² + 2aΔy
(0 m/s)² = v₀ᵧ² + 2 (-10 m/s²) (1.4 m)
v₀ᵧ = 5.29 m/s
The vertical component is 5.29 m/s. So the total magnitude of the initial velocity is:
v₀ᵧ = v₀ sin θ
5.29 m/s = v₀ sin 60°
v₀ = 6.11 m/s
Rounding to two significant figures, the fish must spit the water at 6.1 m/s.