Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
Answer:
2880 packages/min
Step-by-step explanation:
48 × 60 = 2880
15.5 rounded to the nearest tenth is 15.5
Hey Dammy17,
Ok so what we need to do is "plug in" 2oz for x in the equation,
So, 0.6 (2) + 11 =
0.12 + 11= 11.12 oz is the finishing weight.
Answer:
x ≈ 11.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sin∅ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle = 35°
Opposite Leg = <em>x</em>
Hypotenuse = 20
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [sine]: sin35° = x/20
- Isolate <em>x</em>: 20sin35° = x
- Evaluate: 11.4715 = x
- Rewrite: x = 11.4715
- Round: x ≈ 11.5