All categories

2 years ago

Consider functions f and g

Mathematics

1 answer:

Alex2 years ago

7 0

Answer:

1)D 2) Can't see the function

You might be interested in

Don't mind the yt but how/?

Nuetrik [128]

r = 44

12 = r -(34-2)

12 = r -(32)

12 = r-32

r = 32+12

r = 44

5 0

3 years ago

30 ounces at $4.00 per pound. how much was paid for 30 ounces

Nata [24]

It would be $7.50 because 4 ounces equals $1 so 30/4 =7.5

3 0

3 years ago

Please help me i forgot how to do this

ICE Princess25 [194]

Basically, unit rates are special ratios with two different terms with two different units.

1. 3 inches of rain in 6 hours
Answer: 3 inches:6 hours

2. 70 miles in 2 hours
Answer: 70 miles:2 hours.

It's easy!

5 0

3 years ago

Order these ratios from least to greatest- 7:2, 12 to 4, 20/6, 21:14, 10:5<br> pls :,)

Brrunno [24]

Answer:

21:14, 10:5, 12 to 4, 20/6, and 7:2

Step-by-step explanation:

first simplify all the ratios.

the first one is already simplified

12 to 4 = 3 to 1

20/6 = 10/3

21:14 = 3:2

10:5 = 2:1

Next find the least common factor the the three digits, 1, 2, and 3 and which is 6.

Multiply the simplified factors into the least common factor. So 7:2 will be multiplied by 6 so it will be 21:6

Do it with the rest of the factors and get

21:6, 18 to 6, 20/6, 9:6, and 12:6

Finally order them from least to greatest,

9:6, 12:6, 18 to 6, 20/6, and 21:6

21:14, 10:5, 12 to 4, 20/6, and 7:2

4 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago