All categories

3 years ago

Solve: e^2x+5= 4 (for those who want the answer to this!)

Mathematics

1 answer:

olga2289 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

With the way it is written, there are no values of x that make the equation true.

You might be interested in

Write an equation of the graph:

katrin [286]

1. To translate to the left, add to x.
The equation is: y = |x + 2|

2. To translate down, add to y.
The equation is: y + 2 = |x| OR y = |x| - 2 (subtract 2 from each side)

Hope this helps!

5 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

PLEASE HELP NOW!!!!

Nuetrik [128]

Answer:

Step-by-step explanation:

BCCCCCC

6 0

3 years ago

Read 2 more answers

indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and

vladimir1956 [14]

The equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is 12x - 2y = 13.

In the question, we are asked to indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5).

The slope of the line with endpoints (-1,6) and (5,5), can be calculated as:

m = (6 - 5)/(-1 - 5) = 1/(-6) = -1/6.

Thus, the slope of the perpendicular bisector = -1/m = -1/(-1/6) = 6.

The perpendicular bisector passes through the midpoint of the line with endpoints (-1,6) and (5,5), which can be calculated as:

(x₁, y₁) = ( {(-1 + 5)/2},{(6 + 5)/2} ),

or, (x₁,y₁) = (2, 11/2).

Thus, the required equation can be shown as:

(y - 11/2) = 6(x - 2), which can be shown in the standard form as follows:

(2y - 11)/2 = 6x - 12,

or, 2y - 11 = 12x - 24,

or, 12x - 2y = 13.

Thus, the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is 12x - 2y = 13.

Learn more about the equation of perpendicular bisector at

brainly.com/question/20608689

#SPJ4

4 0

2 years ago

5pts and the person who has the correct answer gets brainliest

Tanzania [10]

Answer:

Step-by-step explanation:

The one that weighs the less is 80

Pls give brainlest.

6 0

2 years ago

Read 2 more answers