A baseball is thrown at angle of 65 degrees with an initial velocity of 45 m/s. How long will the baseball remain in the air?
1 answer:
The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.
<h3>What is the maximum height achieved in projectile motion?</h3>It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.
From Newton's first equation of motion;
The time the baseball remains in the air will be twice the time he travels for one side motion;
T' = 2t
T'=2 × 4.68 sec
T'= 9.37 sec
Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.
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Answer:
The displacement was 320 meters.
Explanation:
Assuming projectile motion and zero initial speed (i.e., the object was dropped, not thrown down), you can calculate the displacement using the kinematic equation:
The displacement was 320 meters.