All categories

3 years ago

What is the acceleration of a car at rest that speeds up to 75m/s over 25 seconds?

Physics

1 answer:

Yuki888 [10]3 years ago

6 0

It’s a because I just did it

You might be interested in

A physical property of halite (table salt) is its _____.

nexus9112 [7]

Taste: salty
color: varies. ex: white, clear, purple, yellow, etc.
status: mineral

4 0

3 years ago

A baseball sits motionless near first base on a baseball diamond. What statement

Citrus2011 [14]

Answer:

B. There are no forces acting on the ball.

Explanation:

There are no forces acting on the ball.

5 0

2 years ago

A uniform thin wire is bent into a quarter-circle of radius a = 20.0 cm, and placed in the first quadrant. Determine the coordin

Mashcka [7]

Answer:

$r_{cm}=[12.73,12.73]cm$

Explanation:

The general equation to calculate the center of mass is:

$r_{cm}=1/M*\int\limits {r} \, dm$

Any differential of mass can be calculated as:

$dm = \lambda*a*d\theta$ Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

$\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}$

So, the differential of mass is:

$dm = \frac{2M}{a\pi}*a*d\theta$

$dm = \frac{2M}{\pi}*d\theta$

Now we proceed to calculate X and Y coordinates of the center of mass separately:

$X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta$

$Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta$

Solving both integrals, we get:

$X_{cm}=2*a/\pi=12.73cm$

$Y_{cm}=2*a/\pi=12.73cm$

Therefore, the position of the center of mass is:

$r_{cm}=[12.73,12.73]cm$

5 0

3 years ago

0.75 km expressed in centimeters

disa [49]

75000 lol enjoy..............using up 20 characters

7 0

3 years ago

a man is standing near the edge of a cliff 85 meters high. he throws a stone upward vertically with an intial velocity of 10 m/s

alex41 [277]

Answer:

h = 90.10 m

Explanation:

Given that,

A man is standing near the edge of a cliff 85 meters high, h₀ = 85 m

The initial speed of the stone, u = 10 m/s

The path followed by the projectile is given by :

$h(t)=-4.9t^2+10t+85$ ....(1)

For maximum height,

Put dh/dt = 0

So,

$\dfrac{dh}{dt}=-9.8t+10=0\\\\t=\dfrac{10}{9.8}\\\\=1.02\ s$

Put the value of t in equation (1).

$h(t)=-4.9(1.02)^2+10(1.02)+85\\\\=90.10\ m$

So, the maximum height of the stone is equal to 90.10 m.

5 0

3 years ago