A stuntman is being pulled along a rough road at a constant velocity by a cable attached to a moving truck. The cable is paralle
1 answer:
Answer:
715 N
Explanation:
Since the system is moving at a constant velocity, the net force must be 0. The tension on the road is equal and opposite direction with the kinetic friction force created by the road and the stuntman.
Let g = 9.8 m/s2
Gravity and equalized normal force is:
N = P = mg = 107*9.8 = 1048.6 N
Kinetic friction force and equalized tension force on the rope is
You might be interested in
Answer:
Tension of 132N
Explanation:
We need to apply Summatory of Force to find the tension in the hand.
We define te tensión in the hand as and the Tension in fence post as
, then
We apply summatory of moments then
Where the Force 2 is 1.25m from the center of summatory,
We can note that,
We have two equation and two incognites, then replacing (1) in (2)
Answer:
For the first situation, we first need to find the mass of the second train car.
In order to do that, we apply the conservation of the amount of movement:
and we have as a result:
m2 = 289.6875
For the second situation, also we will apply the conservation of the amount of movement:
and we have as a result:
V = 2.64 (it is moving to the right)