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3 years ago

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A stuntman is being pulled along a rough road at a constant velocity by a cable attached to a moving truck. The cable is paralle

l to the ground. The mass of the stuntman is 107 kg, and the coefficient of kinetic friction between the road and him is 0.682. Find the tension in the cable.

1 answer:

Alex73 [517]3 years ago

6 0

Answer:

715 N

Explanation:

Since the system is moving at a constant velocity, the net force must be 0. The tension on the road is equal and opposite direction with the kinetic friction force created by the road and the stuntman.

Let g = 9.8 m/s2

Gravity and equalized normal force is:

N = P = mg = 107*9.8 = 1048.6 N

Kinetic friction force and equalized tension force on the rope is

$T = F_{\mu} = N\mu = 1048.6 * 0.682 = 715.1452 N$

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We can solve this problem with the following equations:

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<h3>b) Time</h3>

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Since $V_{oy}=0 m/s$ , equation (3) is written as:

$V_{f}=-gt$ (8)

$V_{f}=-(97.22)(17.49 s)$ (9)

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$x=(97.22 m/s)(17.49 s)$ (11)

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raketka [301]

Hello!

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If we want to find the period, we have to express equation (1) as written below and substitute all the values:

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