Question

How to convert from vertex to standard y=2(x-2)^2 -2 to standard

Answer 1

The quadratic equation in standard form is:

$y = 2x^2 - 8x + 6$

How to convert from vertex form to standard?

Here we have the quadratic equation:

$y = 2*(x - 2)^2 - 2$

Here we need to expand the right side, remember:

$(a + b)^2 = a^2 + 2ab + b^2$

Using that, we get:

$y = 2*(x - 2)^2 - 2 = 2*(x^2 - 4x + 4) - 2\\\\y = 2x^2 - 8x + 8 - 2\\\\y = 2x^2 - 8x + 6$

This is the quadratic equation in standard form.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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