Question

complete the square to rewrite y=x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimium and give its coordinates

Answer 1

The vertex form of the Quadratic equation is y =  $(x-3)^{2}$ +5. The vertex is (3, 5), which is a maximum point.

what is a quadratic equation?

A quadratic equation is an algebraic equation with the power of its variable 2.

it can be written in standard form which is called vertex form or in the general form.

Analysis:

y = $x^{2}$ -6x +14

y = $x^{2}$ -6x +9 +5

Simplifying this perfect square expression y = $x^{2}$ -6x +9

y  = $x^{2}$ -3x -3x +9

y = x(x-3) -3(x-3) + 5

y = (x-3)(x-3) +5

y = $(x-3)^{2}$ + 5

In conclusion, the Vertex form of the equation is y = $(x-3)^{2}$ + 5

Learn more about quadratic equation: brainly.com/question/1214333

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