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2 years ago

Comparing Fractions Choose the correct symbol to compare the fractions please see attached image

Mathematics

1 answer:

Elza [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Given: $\frac{1}{2} ? \frac{1}{3}$

Want: Which fraction is larger?

To identify the size of a fraction, converting it into a fraction is easier

$\frac{1}{2}$ = 0.5

$\frac{1}{3}$ = 0.33

where 0.5 is greater than 0.33

Choices:

< is less than symbol

> is greater than symbol

= is equal to

$\frac{1}{2} > \frac{1}{3}$

Learn more about the Fractions at brainly.com/question/280013

Visual Representation:

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How can you tell which end of a worm is his head

Zielflug [23.3K]

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3 years ago

Mia and her 3 friends went out for dinner at a restaurant. Total bill was $ 65.12. All friends are going to divide the bill. How

eduard

Answer:

it would have to be a or b i think

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

(50 points) A diameter of a circle has endpoints P(-10, -2) and Q(4,6)

Gala2k [10]

Answer:

Step-by-step explanation:

The center of the circle is the midpoint of the two end points of the diameter.

Formula

Center = (x2 + x1)/2 , (y2 + y1)/2

Givens

x2 = 4

x1 = - 10

y2 = 6

y1 = - 2

Solution

Center = (4 - 10)/2, (6 - 2)/2

Center = -6/2 , 4/2

Center = - 3 , 2

So far what you have is

(x+3)^2 + (y - 2)^2 = r^2

Now you have to find the radius.

You can use either of the endpoints to find the radius.

find the distance from (4,6) to (-3,2)

r^2 = ( (x2 - x1)^2 + (y2 - y1)^2 )

x2 = 4

x1 = -3

y2 = 6

y1 = 2

r^2 = ( (4 - -3)^2 + (6 - 2)^2 )

r^2 = ( (7)^2 + 4^2)

r^2 = ( 49 + 16)

r^2 = 65

Ultimate formula is

(x+3)^2 + (y - 2)^2 = 65

The radius is √65 = 8.06

8 0

3 years ago

Which expression have the same value as the product of 2.7 and 4

Maurinko [17]

Answer:

Step-by-step explanation:

2.7*4=10.80

27*0.4=10.80 we multiplied 27 by 10 but divide 4 by 10

0.27*40=10.80

3 0

3 years ago

System of Equations Need help Trig

Yanka [14]

Looks like the system is

$\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}$

We can eliminate $y$ by taking

$(3x+2y+5z)-2(-2x+y+6z)=16-2(1)$

$\implies3x+2y+5z+4x-2y-12z=16-2$

$\implies7x-7z=14$

$\implies x-z=2$

so that $z=x-2$ , and

$(7x+3y-4z)-3(-2x+y+6z)=11-3(1)$

$\implies7x+3y-4z+6x-3y-18z=11-3$

$\implies13x-22z=8$

Substitute $z=x-2$ into this last equation and solve for $x$ :

$13x-22(x-2)=8$

$\implies13x-22x+44=8$

$\implies-9x=-36$

$\implies x=4$

Then

$z=x-2$

$\implies z=4-2$

$\implies z=2$

Plug these values into any one of the original equation to solve for $y$ :

$-2x+y+6z=1$

$\implies-2(4)+y+6(2)=1$

$\implies-8+y+12=1$

$\implies y=-3$

Hence the solution is x = 4, y = -3, and z = 2.

6 0

3 years ago