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nexus9112 [7]
2 years ago
6

The area of a circle is 47.39cm2. find the length of the radius rounded to 2 dp.

Mathematics
1 answer:
Tpy6a [65]2 years ago
5 0

The length of the radius rounded to 2 decimal points is 3.88cm.

In geometry, the area enclosed by a circle of radius r is pie  πr^2.

How to round decimals?

Rounding decimals consists of rounding a decimal number to a certain number of decimal places, to save time and help us express really long numbers in shorter terms. There are certain rules to follow when rounding a decimal number. Put simply, if the last digit is less than 5, round the previous digit down. However, if it’s 5 or more than you should round the previous digit up. So, if the number you are about to round is followed by 5, 6, 7, 8, 9 round the number up. And if it is followed by 0, 1, 2, 3, 4 round the number down.

The area of circle is 47.39cm^2.

Putting it in the formula we get

47.39cm^2 = πr^2

r^2 = 47.39 / π

r^2 = 15.0847

r = 3.88 cm

Hence the length of the radius rounded to 2 decimal points is 3.88cm.

Learn more about circles here :

brainly.com/question/22275589

#SPJ4

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Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
miv72 [106K]

Answer:

-1, 1

13, 15

Step-by-step explanation:

x and x+2 are the integers

  • x*(x+2)= 7(x+x+2) -1
  • x²+2x= 14x+14-1
  • x² - 12x -13= 0

Roots of the quadratic equation are: -1 and 13.

So the integers pairs are: -1, 1 and 13, 15

3 0
3 years ago
HELP PLEASE! Write and solve the equation: The squares are identical. What is the area of each square?
Zarrin [17]

If a=4:

HOW TO FIND THE AREA

<h2>A=4a (formula)</h2>

A=4*4

A=16

If it's 100:

A=4*100

A=400

7 0
3 years ago
Read 2 more answers
PLS HELPPPP MEEEE I NEED WORK SHOWN TOO
Elanso [62]

The series of operations for each case are listed below:

  1. GCF / GCF / GCF
  2. GCF / Grouping
  3. Quadratic trinomial
  4. GCF / Quadratic trinomial
  5. Difference of squares
  6. Difference of cubes / Quadratic trinomial
  7. Sum of cubes
  8. GCF / Quadratic trinomial
  9. GCF / Difference of squares

<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

To learn more on polynomials: brainly.com/question/17822016

#SPJ1

7 0
1 year ago
A1<br> B2<br> C3<br> D4<br> what is it
Sonja [21]
I believe four is the right answer to the problem
5 0
3 years ago
What is the value of f?<br><br> −18f−34−14f=11
Brrunno [24]
-18f - 34 - 14f = 11
-32f - 34 = 11
-32f = 45
f = -32/45
Simplify the fraction if needed!
Hope this helps, and please mark brainliest!

6 0
3 years ago
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