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2 years ago

Find two numbers such that one number is 3 less than twice as big as the other number and the two numbers sum to 21.

Mathematics

1 answer:

Hitman42 [59]2 years ago

8 0

Answer:

The two numbers are:

8 and 13

Step-by-step explanation:

a = 2b - 3 Eq. 1

a + b = 21 Eq. 2

Replacing Eq. 1 in Eq. 2:

(2b-3) + b = 21

3b - 3 = 21

3b = 21 + 3

3b = 24

b = 24/3

b = 8

from Eq. 1

a = 2*8 - 3

a = 16 - 3

a = 13

Check:

From Eq. 2:

a + b = 21

13 + 8 = 21

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