2 years ago

Find two numbers such that one number is 3 less than twice as big as the other number and the two numbers sum to 21.

Mathematics

1 answer:

Hitman42 [59]2 years ago

8 0

Answer:

The two numbers are:

8 and 13

Step-by-step explanation:

a = 2b - 3 Eq. 1

a + b = 21 Eq. 2

Replacing Eq. 1 in Eq. 2:

(2b-3) + b = 21

3b - 3 = 21

3b = 21 + 3

3b = 24

b = 24/3

b = 8

from Eq. 1

a = 2*8 - 3

a = 16 - 3

a = 13

Check:

From Eq. 2:

a + b = 21

13 + 8 = 21

You might be interested in

What is .9 times 10 to the -6th power? i really suck at math haha

dexar [7]

0.0000009

.9 times 10 is 9, so then you have to move it back -6 times behind the decimal.

3 0

3 years ago

Can yall help me!! conclude the following data!!

Vinil7 [7]

Answer:

Zoo

4=60

8=120

12=180

16=240

Museum

5=95

10=190

15=285

20=380

ALSOOOO HI BLINK!

5 0

3 years ago

Give a example of two fractions with the quotient of 5/12

olasank [31]

Poorly phrased question, but the general answer is 5k/(12k), where k ∈ Z (i.e. k is an integer).

So, 5/12 and 10/24.

3 0

3 years ago

The sum of 3 consecutive odd numbers is 183,what is the second number in the sequence

Veseljchak [2.6K]

Answer:

Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool. Boy I am cool.

Step-by-step explanation:

4 0

3 years ago

In /\UVW, VW ~= UV and m

goblinko [34]

I’m so sorry but I do not understand the question-could u explain

4 0

3 years ago