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vesna_86 [32]
2 years ago
12

The accompanying diagram show a cross-section of a rectangular pyramid. The cross sectional area is 36in and is 3 inches from th

e vertex of the pyramid. If the height of the pyramid is 5 inches, what is the area of the rectangular base?
Mathematics
1 answer:
LiRa [457]2 years ago
3 0

The area of the rectangular base is the amount of space on the rectangular base

The area of the rectangular base is 60 square inches

<h3>How to determine the area of the rectangular base?</h3>

The question is incomplete; as the diagram is not given.

So, I will apply the concept of similar shapes to determine the area of the rectangular base

To determine the area of the rectangular base, we make use of the following equivalent ratio:

Ratio = Height : Area

This gives

3 : 36 = 5 : Area

Express as fraction

36/3 = Area/5

Evaluate the quotient

12 = Area/5

Multiply both sides by 5

Area = 60

Hence, the area of the rectangular base is 60 square inches

Read more about areas at:

brainly.com/question/24487155

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What is the value of x when solving the equation -x-1=3x-5
Rzqust [24]

<em>x = 1</em>

<em><u>Here is why:</u></em>

-x-1=3x-5

Add x to both sides.

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3 0
3 years ago
The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​
Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

                            a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0
3 years ago
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