Answer:
<h2>See below</h2>
Step-by-step explanation:
I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.
<h3>EQUATION 1: y = x² - 2</h3>
Graph Properties:
Opens up
Vertex is 0, -2
Axis of symmetry is x = 0
Graph photo shown in file called equation 1 graph
<h3>EQUATION 2: y = 2x²</h3>
Graph Properties:
Opens up
Vertex is 0, 0
Axis of symmetry is x = 0
Graph photo shown in file called equation 2 graph
<h3>EQUATION 3: y = (x - 2)²</h3>
Graph Properties:
Opens up
Vertex is 2, 0
Axis of symmetry is x = 2
Graph photo shown in file called equation 3 graph
I'm always happy to help :)
Answer:
1. 41/45.
2. x/(x^2+3x+6)
Step-by-step explanation:
1.
So first we fill the ven diagram.
There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.
now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up
240 + 60 + 110 = 410.
The total possible outcome is 410, and the total outcome is 450, so the answer is
410/450 = 41/45
2.
First, to get the total outcomes, we have to add all the expressions together.
x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.
Since that is the total outcome, we have to find the possible outcomes.
The problem wants BOTH from the 20th century and British, so it is x.
x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer
Answer:
-19,-24,-29
192,768,3072
Step-by-step explanation:
for the first equation its going down by 5
for the second its multiplying by 4 everytime
