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SOVA2 [1]
2 years ago
5

PLEASE HELP! I WILL MARK BRAINLIEST! Which type of lines is shown in the illustration above?

Mathematics
2 answers:
Rainbow [258]2 years ago
6 0
D intersecting lines
lyudmila [28]2 years ago
4 0

Answer:

D. Intersecting lines.

Step-by-step explanation:

The lines are intersecting each other.

The reason it is not perpendicular lines is because perpendicular lines have 90° angles.

Hope this helps!

If not, I am sorry.

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Hello there ^^ I'd love it if you would help me :D
pochemuha
Do you have a question??
3 0
3 years ago
Read 2 more answers
Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.
Galina-37 [17]

Answer:

AD \parallel BC

AB \parallel CD

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0

The slope of side BC is

M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1

The slope of side CD is

M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0

The slope of AD is

M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1

AD \parallel BC

AB \parallel CD

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

4 0
3 years ago
I swear when I actually need help nobody ever answers
Llana [10]

Answer:

stop asking questions and u wont have to worry abt that

Step-by-step explanation:

if u stop asking maybe u wont get an answer

8 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION!!! geometry
Alex17521 [72]

Answer:

i canot help you

Step-by-step explanation:

this is a question that is collage level so i cannot help

4 0
2 years ago
A church is bringing a group of its members to a "clean comedians" show. If they bring 15 people, it will cost $10 each. For eac
ratelena [41]

Answer:

a) $169.2

b) $202.8

c) the church can bring either 31 or 34 members

Step-by-step explanation:

For each person the church brings that exceeds 15, the ticket price goes down by $0.20

18 members exceed 15 by 3.

This means that for 3 persons the church brings that exceeds 15, we have 3*0.20 = $0.60

The price of the ticket will now be

10 - 0.6 = $9.40

For the 18 members, we now have

18*9.4 = $169.2

b) The model for bringing a number of people at a particular cost = C(x)

x is the number of people that exceeds 15

C(x) = (15+x)(10-0.2x)

C(x) = 150 - 3x + 10x - 0.2x^2

= 150 + 7x - 0.2x^2

In bringing 26 people to the show, it is 11 more than 15

C(11) = 150 + 7(11) - 0.2(11)^2

C(11) = 150 +77 - 24.2

= $202.8

c) if the church can only afford $210.8, to solve x, we have

150 + 7x - 0.2x^2 = 210.8

-0.2x^2 + 7x + 150 = 210.8

-0.2x^2 + 7x + 150 - 210.8 = 0

-0.2x^2 + 7x -60.8 = 0

(-b +/-√b^2 - 4ac) / 2a

a = -0.2 , b = 7 c = -60.8

(-7 +/-√7^2 - 4(-0.2)(-60.8)) / 2(-0.2) = 0

(-7 +/-√49 - 48.64) / -0.4 = 0

(-7 +/-√0.36) / -0.4 = 0

(-7 +/- 0.6) / -0.4 = 0

(-7+0.6)/-0.4 or (-7 - 0.6)/-0.4

(-6.4)/-0.4 or (-7.6)/- 0.4

16 or 19

So we have (15+16) = 31 members

(15+19) = 34 members

The church can bring either 31 members or 34 members

8 0
3 years ago
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