(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Find the absolute value vertex. In this case, the vertex for y=|x−5|y=|x-5| is (5,0)(5,0).
(5,0)(5,0)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
(−∞,∞)(-∞,∞)
{x|x∈R}{x|x∈ℝ}
For each xx value, there is one yy value. Select few xx values from the domain. It would be more useful to select the values so that they are around the xx value of the absolute valuevertex.
xy3241506172
Answer:
the first answer is correct Edge 2020
Step-by-step explanation:
Answer:
26 wins , 14 ties
Step-by-step explanation:
Given: Hockey teams receive 
points when they win and 
point when they tie. One season, a team won a championship with 
points. They won 
more games than they tied.
To Find: How many wins and how many ties did the team have.
Solution:
let the number of wins hockey team have 
let the number of ties hockey team have 
Now,
Hockey teams receive points when they win and point when they tie.
They won more games than they tied
Solving both equations we get
Hence, the hockey team have 
wins and 
ties.
The correct answer for the question that is being presented above is this one: "B.a circle with a radius of 4 in." <span>circles have an area of16 pi in2 should have a radius of 4 in.
</span>
The area of a circle is this:
Area = pi * r^2
16 pi = pi * r^2
r^2 = 16
r = 4.
