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Umnica [9.8K]
3 years ago
8

ASAP PLEASE HELP!! SCALE FACTOR! EASY!!

Mathematics
2 answers:
zysi [14]3 years ago
6 0

Answer:

1.6667

Step-by-step explanation:

professor190 [17]3 years ago
6 0
I think it’s 1.666 I’m not sure
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I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?
Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties
  • Reciprocals

<u>Algebra II</u>

  • Log/Ln Property: ln(\frac{a}{b} ) = ln(a) - ln(b)

<u>Calculus</u>

Derivatives

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative of Ln: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

ln(\frac{2x-1}{x-1} )=t

<u>Step 2: Differentiate</u>

  1. Rewrite:                                                                                                         t = ln(\frac{2x-1}{x-1})
  2. Rewrite [Ln Properties]:                                                                                 t = ln(2x-1) - ln(x - 1)
  3. Differentiate [Ln/Chain Rule/Basic Power Rule]:                                         \frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1
  4. Simplify:                                                                                                          \frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}
  5. Rewrite:                                                                                                          \frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}
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  7. Reciprocate:                                                                                                  \frac{dx}{dt} = -(2x-1)(x-1)
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