Answer:
the magnitude of the displacement after 5s is 137.31 m.
Explanation:
Given;
initial velocity of the projectile, u = 60 m/s
angle of projection, θ = 60°
time of motion, t = 5s
the vertical component of the velocity, 
The magnitude of the displacement after 5s is calculated as;
Therefore, the magnitude of the displacement after 5s is 137.31 m.
Answer:
73 degree
Explanation:
Angle of incidence = 17 degree
According to the laws of reflection, the angle of incidence is equal to the angle of reflection.
So, angle of reflection = 17 degree
Angle from the surface = 90 - 17 = 73 degree
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10
Answer:
0.237 (23.7 %)
Explanation:
The thermal efficiency of an engine is given by:
where
W is the useful work output of the engine
is the heat in input
Here we have:
and the work done is the total heat in input minus the heat exhausted:
So, the efficiency is
(23.7 %)
C.) Year
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