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VladimirAG [237]
3 years ago
9

Calculate the force at sea level that a boy of mass 50 kg exerts on a chair in which he is sitting

Physics
1 answer:
kirill115 [55]3 years ago
7 0
There is only one force applying to the boy, which is gravity in that regard pointing from the chair down to earth. The gravity force "Fg" is equal to the mass "m" of the object multiply by the earth accelaration "g". And so F = 50kg.9.8m/s = 490Newtons (N)
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Which of the following is a process that occurs at divergent boundaries?
PIT_PIT [208]
The appropriate answer is 4. The formation of Mid-Ocean ridges. There are two types of divergent margins: continental separation and oceanic floor spreading. Where the sea floor separates magma upwells and new oceanic crust is formed. Mid ocean ridges are home to hydrothermal vents. These support a unique ecosystem of marine organisms. The Mid- Atlantic Ridge where the African and Eurasian plates separate from the North and South American plates.
7 0
3 years ago
A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo
Rasek [7]

Answer:

t=12.25\ seconds

Explanation:

<u>Diagonal Launch </u>

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

x=v_ocos\theta t

\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}

Where vo is the magnitude of the initial velocity, \theta is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

\displaystyle t=\frac{v_osin\theta}{g}

There are two times where the value of y is y_o when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making y=y_o

\displaystyle y_o=y_o+v_osin\theta\ t-\frac{gt^2}{2}

Removing y_o and dividing by t (t different of zero)

\displaystyle 0=v_osin\theta-\frac{gt}{2}

Then we find the total flight as

\displaystyle t=\frac{2v_osin\theta}{g}

We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is

\boxed{t=24.5/2=12.25\ seconds}

4 0
3 years ago
What percent of $ 40 is $ 32?<br><br>​
kumpel [21]

Answer:

80%

Explanation:

convert fraction ( ratio ) 32/40 answer 80%

4 0
4 years ago
Read 2 more answers
What is the thermal efficiency of a gas power cycle using thermal energy reservoirs at 627°C and 90°C?
vlada-n [284]

Answer:

The value is \eta = 63\%

Explanation:

Generally the thermal efficiency is mathematically represented as

\eta =  1 -  \frac{T_L}{T_H} * 100

substituting  [ 627°C + 273  =  900K ]  for  T_H and    [ 90°C + 273  =  333K ]  for T_L

   So  

         \eta =  1 -  \frac{333}{900} *100

=>     \eta = 63\%

5 0
3 years ago
Question 3 (Essay Worth 5 points)
Elis [28]
Well, in order to figure out the answer is to divide until you figure out how many miles they went per second. If it takes 5 seconds to reach 50 miles per hour it took 10 seconds per every 10 miles meaning each mile took 1 second. (Not actually possible but the answer) So, If it finished a 100 mile trip in 2 hours it took an hour for 50 miles. If it took 1 hour for 50 miles divide 60/50 which gets you 1.2 so it took 1.2 miles per minute meaning the car went 120 miles per hour I believe. I hope this helps :)
8 0
3 years ago
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