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AVprozaik [17]
3 years ago
13

A bowling ball rolls 33\,\text m33m33, start text, m, end text with an average speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2

, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. How many seconds did the ball roll?
Physics
1 answer:
asambeis [7]3 years ago
4 0

The ball rolled for 13.2 s

<h3>Further explanation</h3>

Speed is scalar and no direction

\tt avg~speed=\dfrac{total~distance}{elapsed~time}=\dfrac{\Delta x}{\Delta t}

A bowling ball rolls 33 m, with average speed = 2.5 m/s

So elapsed time :

\tt t=\dfrac{33~m}{2.5`m/s}=13.2~s

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