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3 years ago

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A bowling ball rolls 33\,\text m33m33, start text, m, end text with an average speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m 2

, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. How many seconds did the ball roll?

1 answer:

asambeis [7]3 years ago

4 0

The ball rolled for 13.2 s

<h3>Further explanation</h3>

Speed is scalar and no direction

$\tt avg~speed=\dfrac{total~distance}{elapsed~time}=\dfrac{\Delta x}{\Delta t}$

A bowling ball rolls 33 m, with average speed = 2.5 m/s

So elapsed time :

$\tt t=\dfrac{33~m}{2.5`m/s}=13.2~s$

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In a fluorescent tube of diameter 4.8 cm , 2.7 × 1018 electrons (with a charge of −e) and 2.4 × 1018 positive ions (with a charg

Lesechka [4]

Answer: 0.817A

Explanation:

Assuming , that one coulomb per second of negative charge alone flow through a conductor and no positive charges flow. I.e Q=It

It means a current of one A flow in the opposite direction.

This is similar to one coulomb per second of positive charge flowing through and there is no negative charge,

In addition, the one coulomb per second of positive charge flows. This is flowing in the current direction of the previous one. Then, the total current is 2 A. Since 2 coulomb of positive charges flow through one due to real positive charge and another due to the negative charge flowing in opposite direction.The charges cannot cancel each other, because even before the current flow the conductor was neutral.

According to this, the current in the given problem is

[2.7 + 2.4] x 10 ^ 18 * 1.602 x 10^ [-19] C/s

= 0.817 A

7 0

3 years ago

A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?

iris [78.8K]

Answer:

$\Delta x=22.67786838m$

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

$y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2$ (1)

Where:

$y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis$

$y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis$

$v_o=initial\hspace{3}velocity$

$t=travel\hspace{3}time$

$g=gravity\hspace{3}constant$

$\theta=Initial\hspace{3}launch\hspace{3}angle$

In this case:

$\theta=0$

Because the dog jumps horizontally

Let's asume the gravity constant as:

$g=9.8$

$y=0$

Because when the dog reach the base the height is 0

$y_o=70$

$v_o=6$

Now let's replace the data in (1)

$y_o-\frac{1}{2} *(9.8)*t^2+70$

Isolating t:

$t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473$

Finally let's find the horizontal displacement using this equation:

$\Delta x=v_o*cos(\theta)*t$

Replacing the data:

$\Delta x=6*1*3.77964473=22.67786838m$

8 0

2 years ago

Metal sphere A is hung from the ceiling by a long, thin string and given a positive charge. An identical sphere B is suspended n

IrinaK [193]

Answer:

A decreases while B increases because the equilebrium only reacts to different sphers of this substance.

Explanation:

7 0

3 years ago

Please help! 100 points + 50 + brainlist!!!

irakobra [83]

Explanation:

First find the displacement in the x direction:

dₓ = 449 cos 66° + 1112 cos 169° + 1571 cos 26°

dₓ = 182.6 − 1091.6 + 1412

dₓ = 503 km

Next, find the displacement in the y direction:

dᵧ = 449 sin 66° + 1112 sin 169° + 1571 sin 26°

dᵧ = 410.2 + 212.2 + 688.7

dᵧ = 1311 km

The magnitude is:

d² = dₓ² + dᵧ²

d² = (503)² + (1311)²

d = 1404 km

The angle is:

tan θ = dᵧ / dₓ

tan θ = 1311 / 503

tan θ = 2.61

θ = 69°

1404 km and 69° north of east from New Orleans is approximately Toledo.

4 0

3 years ago

Read 2 more answers

A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray

mel-nik [20]

Answer:

$45.19^{\circ}$

Explanation:

We are given that

$n_1=1.33$

$n_2=1.6$

$\theta_1=58.6^{\circ}$

We have to find the angle of refraction.

By Snell's law

$n_1sin\theta_1=n_2sin\theta_2$

Substitute the values

$1.33sin58.6=1.6sin\theta_2$

$sin\theta_2=\frac{1.33sin58.6}{1.6}$

$sin\theta_2=0.7095$

$\theta_2=sin^{-1}(0.7095)=45.19^{\circ}$

Hence, the angle mad by refracted ray in to the glass with normal= $45.19^{\circ}$

7 0

3 years ago