Assuming the power delivered by the horse does not change, the speed of the cart will decrease.
In fact, the power delivered by the horse is the work done by the horse (W) per unit time (t):

<span>If several bags are added to the cart, the horse must do more work to transport them. Therefore, W in the fraction increases. But if the power P of the horse is constant, then it means that the time t must increase as well. So, the horse will take more time to transport the car, and this means that the speed of the cart has decreased.</span>
Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length



For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength

Put the value into the formula


We need to calculate the frequency of the tuning
Using formula of frequency

Put the value into the formula



Hence, The frequency of the tuning is 1.065 kHz
It depends, What is the balloon filled with? Just air, heilum, water, etc. If its just air then the bowling ball would most likly hit first, but if the balloon is filled with water it would problably hit at the same time, theres also air resistace to think about is there any or it is almost like a vaccum chamber?
Answer:
Vector has a direction and a magnitude, scalar only has a magnitude
Explanation: