Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
Answer: State
Explanation:
The rock on the left is more shiny than the right, so that’s incorrect.
The rocks are not the same color, so that’s also incorrect.
Even though you can’t feel the textures, the right rock looks grainy and the left on doesn’t.
They both are solid, so that is the correct answer.
Im taking lambda as x (wavelength)
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
To squeeze a gas into a dmaller place is to compress it.
