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Lisa [10]
3 years ago
13

What is the volume in liters of 3.80 moles of CO2gas at STP?

Chemistry
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

V = 85.2

Explanation:

STP = 273K and 1 atm

Considering what we know about STP, we get the moles, temperature, and pressure. Using the ideal gas law we can find the volume (PV = nRT). Plug in our variables: (1 * V = 3.80 * R * 273). Since we are dealing with atm and not kPA or mmHg, we use the constant for atm (0.0821) which we use for R. (So.. now our equation is 1 * V = 3.80 * 0.0821 * 273). We now multiply the right side to get 85.17054. So... V = 85.2 considering sigificant figures (this is the part where I am the least sure of, since I havent done sig figs in a while)

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<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

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_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

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