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ozzi
3 years ago
12

Which one of the following represents an acceptable set of quantum numbers for an electron in an atom? (arranged as n, 1, m, and

ms ) A) 3, 2, -2, -1/2 B) 3, 3,-4, 1/2 C) 3,2,0,0 D) 3,3,3, -1/2 E) 3, 4, 6, -1/2 A-2
Chemistry
1 answer:
babymother [125]3 years ago
4 0

Answer:

The correct option is A) 3, 2, -2, -1/2.

Explanation:

Quantum numbers represent different properties regarding the level, sublevel and orbital in which an electron is. There are 4 quantum numbers:

  1. Principal quantum number (<em>n</em>): indicates the level of energy and gives information about the size of an orbital. It can only take positive and integer values, e. g., 1, 2, 3...
  2. Angular quantum number (<em>l</em>): indicates the sublevel of energy and provides information about the shape of the orbital. Some common shapes are spherical (<em>l</em>=0) and polar(<em>l</em>=1). Shapes for bigger l are more complicated. <em>l</em> values depend on <em>n</em> values. <em>l</em> values can be integers up to (<em>n</em>-1). For example. if <em>n</em> = 2, <em>l</em> can take the values 0 and 1.
  3. Magnetic quantum number (<em>m</em>): it gives information about the orientation in space of an orbital. It may take any integer value between -l and +l. For example, if <em>l</em> = 1, <em>m</em> can take values -1, 0 and 1, each one referring to an orbital p along a different axis in the space (x, y and z axes).
  4. Spin quantum number (<em>ms</em>): it refers to the spin angular momentum of an electron and it can take 2 values:  -1/2 or +1/2.

A) 3, 2, -2, -1/2 is correct because it follows every rule.

B) 3, 3,-4, 1/2 is wrong because if <em>n</em>=3, <em>l</em> can only be up to 2, and l from -3 to +3.

C) 3,2,0,0 is wrong because <em>ms</em> cannot take the value 0.

D) 3,3,3, -1/2 is wrong because if <em>n</em>=3, <em>l</em> can only be up to 2.

E) 3, 4, 6, -1/2 is wrong because if <em>n</em>=3, <em>l</em> can only be up to 2, and <em>l</em> from -3 to +3.

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1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
3 years ago
If someone consumes 22 g of sodium chloride per day, what mass (in grams) of sodium does that person consume? Sodium chloride is
kompoz [17]

Answer:

Mass of sodium, the person daily consume = 8.58 g

Explanation:

Given that:-

sodium chloride is 39% sodium by mass which means that:-

100 g of sodium chloride contains 39 g of sodium

Also,

1 g of sodium chloride contains 0.39 g of sodium

So, Given mass = 22 g

22 g of sodium chloride contains 0.39\times 22 g of sodium

<u>Mass of sodium, the person daily consume = 8.58 g</u>

4 0
3 years ago
How many grams of sodium oxide can be synthesized from 17.4 g of sodium? assume that more than enough oxygen is present. the bal
Tatiana [17]
Equation is as follow,

<span>                          4 Na (s)  +  O</span>₂ <span>(g)    →    2Na</span>₂<span>O (s)

According to equation,

      91.92 g (4 moles) of Na produces  =  123.92 g (2 moles) of Na</span>₂O
So,
                    17.4 g of Na will produce  =  X g of Na₂O

Solving for X,
                                   X  =  (17.4 g × 123.92 g) ÷ 91.92 g

                                   X  =  23.45 g of Na₂O
7 0
3 years ago
Thallium consists of 29.5%Th-203 and 70.5%Th-205. What is the relative atomic mass of thallium?
grin007 [14]
0.295 * 203 = 53.885
0.705 * 205 = 144.525
53.885 + 144.525 = 204.41
The relative atomic mass of Thallium is 204.41 
7 0
3 years ago
Read 2 more answers
There are two common oxides of copper; one is 80% copper and the other is 89% copper by weight. Calculate the formula and name e
irakobra [83]

80% copper (Cu)

Cu: 80 :  63.546 = 1.259

O: 20 : 16 = 1.25

Cu:O = 1 : 1

the formula: CuO

89% copper (Cu)

Cu: 89 :  63.546 = 1.4

O: 11 : 16 = 0.6875

Cu:O = 2:1

the formula: Cu₂O

8 0
2 years ago
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