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ioda
3 years ago
15

1. How many atoms are there in 1.7 mol Ca?

Chemistry
2 answers:
ella [17]3 years ago
7 0

answer: 3g. 17kg+3 ÷ 0.25

Dominik [7]3 years ago
5 0

There are 2.55\times10^{23} atoms in 1.7 mol Ca

<u>Solution:</u>

Initially we have to convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is 40.08  g/mol

1.7 \text { g Ca }\left(\frac{1 \text{ mol Ca}}{40.08 \text{ g Ca}}\right)= 0.0424 \text{ mol Ca}

Using Avogadro's number, 6.022 \times 10^{23} \text{ particles per mol} as 1 \text{ mole }=6.022\times 10^{23}

We can calculate the number of atoms present by 0.0424 \text{ mol Ca}\times\frac{6.022 \times 10^{23}}{1 \text{ mol }}=2.55\times10^{23} \text { atoms Ca }

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An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
Determine the electron configuration of nitrogen numerically.
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Explanation:

atomic number is 7 hence it shuld be 2,5 if numerically.. tho the standard notation is the above giver answer

5 0
3 years ago
Read 2 more answers
Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.
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Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
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Formula:
p*V =n*R*T

Solving:
p*V =n*R*T
8.07*V = 0.352*0.082*298
8.07V \approx 8.60
V \approx  \frac{8.60}{8.07}
\boxed{\boxed{V \approx 1.06\:L}}
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