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never [62]
2 years ago
15

vanillin is a flavoring agent in vanilla it has a mass percent composition of 61.15% c,5.3%H,31.55% o determine the empirical fo

rmula and molecular formula if molecular mass of vanillin is 152.15%g/mol
Chemistry
1 answer:
Nutka1998 [239]2 years ago
6 0

The empirical and molecular formulas will be  C_5H_5O_2 and  C_1_0H_1_0O_4 respectively.

<h3>Empirical and molecular formula</h3>

The compound contains C, H, and O.

C = 61.15/12 = 5.0958

H = 5.3/1 = 5.3

O = 31.55/16 = 1.9719

Divide by the smallest

C = 2.6

H = 2.7

O = 1

Thus, the empirical formula is C_5H_5O_2

Empirical formula mass = (12x5) + (1x5) + 16x2 = 97

n = 152.15/97 = 2

The molecular formula is C_1_0H_1_0O_4

More on molecular and empirical formulas can be found here: brainly.com/question/14425592

#SPJ1

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\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2

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CH3 + HCl &lt;=&gt; CH3Cl + H2O
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Answer:

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Step 3: Calculate the pressure at the equilibrium

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