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Usimov [2.4K]
2 years ago
13

2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.

Chemistry
1 answer:
RideAnS [48]2 years ago
5 0

The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

  • V1 = 2L
  • V2 = ?
  • T1 = -25°C + 273 = 248K
  • T2 = 273K

2/248 = V2/273

273 × 2 = 248V2

546 = 248V2

V2 = 546/248

V2 = 2.2L

Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

Learn more about volume at: brainly.com/question/11464844

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Answer:

Explanation:

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3 years ago
Each of the following reactions is allowed to reach equilibrium in a sealed container. For which of the reactions could you shif
natta225 [31]

Answer:

None of the reaction will be favored to the right by a decrease in pressure.

Explanation:

       CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)  

       CaCO₃(s) ⇄  CaO(s) + CO₂(g)  

       Br₂(g) + 3Cl₂(g) ⇄  2BrCl₃(g)  

       2H₂S(g) + 3O₂(g) ⇄  2SO₂(g) + 2H₂O(g)

From Le Chatellier's principle, we must understand that pressure changes only affects reactions in gaseous phases. The second reaction will not be affected by pressure.

We are now left with three equations.

Also, increase in pressure favors sides with lower volume. We can know the volume from the coefficients in the equation. Now let us check the volumes:

          CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)  

         3 moles of gases      3 moles of gases

        Br₂(g) + 3Cl₂(g) ⇄  2BrCl₃(g)  

         4 moles of gases     2 moles of gases

       2H₂S(g) + 3O₂(g) ⇄  2SO₂(g) + 2H₂O(g)

        5 moles of gases      4 moles of gases

None of the reaction will be favored to the right by a decrease in pressure.

The first reaction will not be affected by any change in pressure because the total number of moles on the two sides are equal.

The last two reactions will be favored to the right by increasing pressure and a decrease in pressure will favor the backward left reaction.

7 0
3 years ago
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butalik [34]
Flowing water of course
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3 years ago
Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).
likoan [24]

Answer:

1.40*10⁻² M

Explanation:

We have the solubility formula

Solubility,

S = KH*P  

where

KH = measure of hardness of water / carbonate hardness = 3.50*10⁻² mol/L.atm

P = atmospheric pressure = 0.400 atm

Hence, we have

S = KH*P

= (3.50*10⁻² mol/L.atm)*(0.400 atm)

= 1.40*10⁻² mol/L

But 1 mol/L = 1 M,

Hence, the answer (1.40*10⁻² mol/L ) is equivalent to

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Answer:

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Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

5 0
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