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<u>Answer:</u> The freezing point of solution is -5.11°C
<u>Explanation:</u>
Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:
The total number of ions present in the solution are 2.
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (NaCl) = 7.57 g
= Molar mass of solute (NaCl) = 58.44 g/mol
= Mass of solvent (liquid X) = 350.0 g
Putting values in above equation, we get:
To calculate the depression in freezing point, we use the equation:
where,
i = Vant hoff factor = 2
= molal freezing point depression constant = 6.90°C/m
m = molality of solution = 0.370 m
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
= 5.11 °C
Freezing point of water = 0°C
Freezing point of solution = ?
Putting values in above equation, we get:
Hence, the freezing point of solution is -5.11°C