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Natasha_Volkova [10]
2 years ago
12

Please help me. NO LINKS!!​

Mathematics
2 answers:
stiks02 [169]2 years ago
6 0

The domain (input values) of the cosine function is all negative and positive angle measures.

Let the function be f(x) = cos(x)

The domain of cos(x) is -∞ < x < ∞

The range is -1 ≤ f(x) ≤ 1

Hence, domain of cos(x) is all (+) and (-) angle measures.

Same goes with sine function as well

For function f(x) = sin(x)

The domain is -∞ < x < ∞ and range -1 ≤ f(x) ≤ 1

However for f(x) = tan(x) the same is not applicable.

NikAS [45]2 years ago
3 0

Answer:

A.  all negative and positive angle measures.

Step-by-step explanation:

The domain of a function is the set of input values (x-values).

The cosine function is a <u>continuous function</u>, and therefore has <u>no restrictions</u> throughout its domain.

Therefore, its domain is all real numbers.

<u>Set notation</u>:  { x | x ∈ R }

<u>Interval notation</u>: (-∞, ∞)

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

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========================================================

Explanation:

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