You could simplify this work by factoring "3" out of all four terms, as follows:
3(x^2 + 2x - 3) =3(0) = 0
Hold the 3 for later re-insertion. Focus on "completing the square" of x^2 + 2x - 3.
1. Take the coefficient (2) of x and halve it: 2 divided by 2 is 1
2. Square this result: 1^2 = 1
3. Add this result (1) to x^2 + 2x, holding the "-3" for later:
x^2 +2x
4 Subtract (1) from x^2 + 2x + 1: x^2 + 2x + 1 -3 -1 = 0,
or x^2 + 2x + 1 - 4 = 0
5. Simplify, remembering that x^2 + 2x + 1 is a perfect square:
(x+1)^2 - 4 = 0
We have "completed the square." We can stop here. or, we could solve for x: one way would be to factor the left side:
[(x+1)-2][(x+1)+2]=0 The solutions would then be:
x+1-2=0=> x-1=0, or x=1, and
x+1 +2 = 0 => x+3=0, or x=-3. (you were not asked to do this).
Answer: 11 < x < 35
suppose: the length of the third side is x
because x is the third side of a triangle
=> 23 - 12 < x < 23 + 12
⇔ 11 < x < 35
Step-by-step explanation:
Here we will tell you what 329 is rounded to the nearest hundred and also show you what rules we used to get to the answer. First, 329 rounded to the nearest hundred is:
300
<span>Remember, we did not necessarily round up or down, but to the hundred that is nearest to 329.</span>
Okay, let's add the two x values.
10x + 75 = 5x = 110
15x + 75 = 110
Now let's minus 75 from each side.
15x = 35
Now let's divide each side by 15.
x = 2.333333333
JK = MN because of Given
∠JLK = ∠MLN because of the vertical angle theorem
JL = LN because of definition of midpoint
ΔJLK = MLN because of SAS
∠K = ∠N because corresponding angles of congruent triangles are congruent.
Hope this helps!<span />
