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kykrilka [37]
2 years ago
14

You randomly select one card from a 52 card deck find the probability of selecting a ace or a two

Mathematics
1 answer:
balu736 [363]2 years ago
3 0
The odds of picking an ace or a 2 are 8 out of 52 or 8/52 or 2/13.
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What's 3,897.003 in expanded form.
Art [367]
3,897.003 in expanded form is:

3,000 + 800 + 90 + 7 + 0.003
3 0
3 years ago
2x - m x= 4 m= 2 can you help me because I wanna know what the answer
NeTakaya

Answer:

6

Step-by-step explanation:

2x-m

When you substitue in the values for x and m:

2(4)-2

Now you can solve the equation:

2(4)-2

8-2

6

So this leads to the answer

2x-m=6 or 2(4)-2=6

6 0
3 years ago
Solve t/12=4 what is the solution for t?
GaryK [48]

Answer:

thx for the points the answer is 3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Math help please (80 points)
Inga [223]

Answer:

1. x^4 -x^3 -4x^2 -3

a1 = -7.4

an = an-1 -13.8  (choice 1)

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We are subtracting

f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)

Distribute the minus sign

x^4 -x^2 +9 -  x^3 -3x^2 -12

I like to line them up vertically

x^4      -x^2 +9

-  x^3 -3x^2 -12

-------------------------

x^4 -x^3 -4x^2 -3


2.  a1 = -7.4

To find the common difference, take term 2 and subtract term 1

-21.2 - (-7.4)

-21.2 + 7.4

-13.8

an = an-1 -13.8

5 0
3 years ago
Read 2 more answers
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
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