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Snezhnost [94]
2 years ago
15

The triathletes were offered water as they rode by the volunteer station. The volunteers handed them cones with the dimensions s

hown. If each triathlete sloshed 1/3 of the water out before they drank it, how many cubic cm of water did they slosh out? Round to the nearest tenth.
Height 7cm
radius 3.5cm
Mathematics
1 answer:
Zolol [24]2 years ago
7 0
Find the area of the cone:
Area of cone: ⅓r^2h
⅓r^2h
= ⅓(3.5)^2(7)
= ⅓(12.25)(7)
= 1/3(85.75)
= 85.75/3
1/3 cup sloshed out:
(85.75/3 )/3
= 29.9 cubic cm
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(3.9 x 10^20)(2.3x10^60) please explain will give Brainliest answer
Lunna [17]

Answer:

(8.97x^2) *(10^80)

Step-by-step explanation:

See attachment

8 0
3 years ago
How do I find X for 3x-7=5x-13?
Westkost [7]
3x - 7 = 5x - 13
-3x        -3x

5x - 3x = 2x

-7 = 2x - 13
+7         +7

-13+7 = -6

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Answer: x = -3
6 0
3 years ago
What is the length of the base of a right triangle with an area of 20m2 and the height of 4 m
Eva8 [605]

Answer:

The base is 10 meters

Step-by-step explanation:

The area of a right triangle is (b × h) ÷ 2 = a

Let's input the given values and find the value of b:

(b × 4) ÷ 2 = 20

4b ÷ 2 = 20

2b = 20

b = 10

Check:

(10 × 4) ÷ 2 = 20

40 ÷ 2 = 20

20 = 20

It works!

8 0
3 years ago
One x-intercept for a parabola is at the point (-0.4,0). Use the quadratic formula to find the other x-intercept for the parabol
navik [9.2K]

Answer:

-1

Step-by-step explanation:

Set y=0.

5 {x}^{2}  + 7x + 2 = 0 \\ x =  \frac{ - 7± \sqrt{ {7}^{2}  - 4(5)(2)} }{2(5)}  \\ x =   \frac{ - 7± \sqrt{ 9} }{10}  \\ x =   \frac{ - 7±3}{10} \\ x =  -  \frac{2}{5}  \:  \:  \:  \: or \:  \:  \:  \:  - 1

The x-intercepts are - 0.4 and - 1.

The other x-intercept is - 1.

6 0
3 years ago
Factorize of 2a³-a²+a-2​
IrinaK [193]
<h3>Answer:  (a - 1)(2a² + a + 2)</h3>

=========================================================

Explanation:

Use the rational root theorem to determine this list of possible rational roots: 1, -1, 1/2, -1/2

Plug each possible root one at a time into the original expression given. If the simplified result is 0, then that possible root is an actual root.

If we tried say a = -1, then,

2a³-a²+a-2​ = 2(-1)³-(-1)²+(-1)-2​ = -6

The result is not zero, so a = -1 is not an actual root.

But if we tried say a = 1, then,

2a³-a²+a-2​ = 2(1)³-1²+1-2​ = 0

We get 0 so a = 1 is an actual root. I'll let you try the other values, but you should find that a = 1 is the only rational root.

Since a = 1 is a root, this makes (a-1) to be a factor.

From here, use either synthetic or polynomial long division to determine the other factor. Refer to the diagram below for each method.

Regardless of which method you pick, the quotient is 2a² + a + 2 which is the other factor needed. The remainder of 0 tells us we have (a-1) as a factor. For more information, check out the remainder theorem.

5 0
2 years ago
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