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coldgirl [10]
3 years ago
11

What is the perimeter of this shape?

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0

Answer:142in

Step-by-step explanation:

Eduardwww [97]3 years ago
4 0
98 inches is the correct answer.
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What is the value of the expression 2w-2 when 5=w
ycow [4]
2w - 2
w = 5

2(5) - 2
10 - 2 = 8

The value would be 8
3 0
3 years ago
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Which symbol would make the number sentence true 8/11 ? 0.73
Nikitich [7]

Answer:

0.73 is greater than 8/11 so the answer is B

Step-by-step explanation:

if you make 8/11 into a decimal its 0.727273 which is less than 0.73

6 0
3 years ago
Will give Brainliest!!!
IgorLugansk [536]

Answer:

B = -0.03t + 0.24

Step-by-step explanation:

Given: battery is at 24% when Logan leaves the house; it loses 3% per hour.

"T" is a placeholder for every hour. In one hour, the phone will be at 21%.

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3 years ago
The sum of three consecutive natural numbers is 1251 find the numbers
valentinak56 [21]

Numbers are 416, 417 and 418

<u>Step-by-step explanation:</u>

Step 1:

Let the numbers be x, x + 1 and x + 2. Given that their sum is 1251.

⇒ x  + x + 1 + x + 2 = 1251

⇒ 3x + 3 = 1251

⇒ 3x = 1248

⇒ x = 416

Step 2:

Find the other numbers.

⇒ x + 1 = 417 and x + 2 = 418

8 0
3 years ago
20 POINTS!!! I GIVE BRAINLIEST PLEASE HELP!!!!A circle with a circumference of approximately 15.71 inches drawn inside a square,
Oksi-84 [34.3K]

answer:

5.002 inches

step-by-step explanation:

  • find the diameter of the circle
  • the diameter is the side length of the square since the sides of it are touching the circle

c = 2πr

  • c stands for circumference
  • π stands for pi (or 3.14)
  • r stands for radius

- plug in the values given to find the diameter

c = 2πr

15.71 = 2(3.14)r

15.71 = 6.28r

r = 2.501 (rounded or estimated)

  • now that we have the radius, we can find the diameter by multiplying by 2, since diameter is two times bigger than the radius

diameter = 5.002 (estimated)

  • now, that will be the side length because the diameter = the side length
3 0
3 years ago
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