Answer:
10.29 cm/s
Explanation:
Discharge in to the bowl = 17.0 cm³/s
Diameter of the bowl, d₁ = 1.45 cm
Now,
Rate at which water level rise at its diameter = 
also,
Area of cross-section = 
or
Area of cross-section = 1.651 cm²
Therefore,
Rate at which water level rise at its diameter = 
or
Rate at which water level rise at its diameter = 10.29 cm/s
-- An object acted on by only the force of gravity, on or near Earth's surface,
accelerates downward at the rate of about 9.8 m/s² without air resistance.
-- That number is "the acceleration due to gravity, on Earth".
-- The object in that situation is said to be in "free fall".
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation:
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
They use a spectrograph so the answer would be B.
