When the life preserver is dropped from the helicopter, the only force acting on the object is the gravitational force. This modifies the equations of motion. Thus, the working equation is written below:
h = vt + 0.5gt²
where
v is the initial velocity
g is the acceleration due to gravity equal to 9.81 m/s²
h is the height of the fall
h = (1.46 m/s)(1.8 s) + 0.5(9.81 m/s²)(1.8 s)
h = 11.457 m
The law of conservation of energy states that energy is neither created nor destroyed; the amount remains constant. For example, a form of energy-thermal energy, or heat, occurs by convection or conduction
Answer:
Initial Velocity = 0 m/s
Final Velocity = 34.6 m/s
time = 3.5 s
Explanation:
The initial velocity must be zero since, the egg must be at rest initially, before dropping.
<u>Initial Velocity = 0 m/s</u>
Now, for time we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = Height = 61 m
Vi = Initial Velocity = 0 m/s
g = 9.8 m/s²
t =time = ?
Therefore,
61 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t² = (61 m)(2)/(9.8 m/s²)
t = √(12.45 s²)
<u>t = 3.5 s</u>
Now, for final velocity we will use 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.6 m/s
Answer: Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC.
Explanation:
