Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
Step-by-step explanation:
Please see the attached picture for the full solution.
Diameter of the circle in the middle = 8 ft
Radius of the circle in the middle :
Thus, the radius of the circle in the middle = 4 ft
Area of the entire circle :
Thus, the area of the entire circle = 314 ft
Area of the circle in the middle :
Thus, the area of the circle in the middle = 50.24 ft
Area of the shaded portion :
= Total area of the figure - Area of the circle in middle
▪︎Therefore, the area of the shaded portion = <u>263.76 ft</u>
Answer:
Length of arc = central angle made by the arc/360° × 2πr
