Please help, i have been doing this for a while and it is still wrong.
1 answer:
Answer:
51.7661748226 degrees; 38.2338251774 degrees
Step-by-step explanation:
First, draw a diagram to illustrate this situation. Looking at angle A, Eric's height, 1.65 m, corresponds to OPPOSITE, and Eric's shadow, 1.30 m, corresponds to ADJACENT. Using SOH CAH TOA, the equation is:
tan(A) = 1.65/1.30
A = arctan(1.65/1.30)
A = 51.7661748226 deg
Looking at angle B, 1.65 m is ADJACENT and 1.30 m is OPPOSITE. Therefore, the equation is:
tan(B) = 1.30/1.65
B = arctan(1.30/1.65)
B = 38.2338251774 deg
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Answer:
a. P(x>20)=0.19
b. P(x≥6)=0.72
c. P(x≤20)=0.81
d. A and C
Step-by-step explanation:
We know that:
1) the probability that a student makes fewer than 6 mistakes is 0.28
2) The probaiblity that a student makes between 6 to 20 mistakes is 0.53.
We will express the proabilibities in function of the information we have.
a. Probability that a student makes more than 20 mistakes.
b. Probability that the student make 6 or more mistakes
c. Probability that a student makes 20 mistakes at most
d. A and C, because A takes a event of more than 20 mistakes and C takes the event of 20 or less mistakes. Both events cover a probability of 1.