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Flura [38]
2 years ago
7

Chlorine and bromine have very similar chemical properties. This is best explained by the fact that both elements:

Chemistry
1 answer:
34kurt2 years ago
7 0

What is the similarity between chlorine and bromine?

Chlorine and bromine have very similar chemical properties and are best explained by the fact that they both belong to the category of halogens.

Similarities shared by halogens:

Chemical elements are represented as periods and groups on a periodic table. Chemical elements with comparable properties make up each category. Halogens are group 17 elements that are primarily non-metallic.

In the case of halogens, each element's atom possesses seven valence electrons, ns^{2} np^{5}, in which n stands for the energy level. The electron configuration of chlorine is [Ne]3s^{2} 3p^{5}, and the electron configuration of bromine is [Ar]3d^{10}4s^{2} 4p^{5}.

Because of comparable electron configurations, elements of the same group have similar properties. The number of valence electrons, which are located in the outermost (highest energy) s and p orbitals, is particularly similar.

Learn more about halogens here;

brainly.com/question/4725757

#SPJ4

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Answer:

63.6%

Explanation:

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The problem here is to find the percent composition of nitrogen in the compound.

First find the molar mass of the compound:

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So;

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Read 2 more answers
Part A
Elden [556K]

Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

ΔG (NO2) = 51.84 kJ/mol

ΔG (N2O4)  = 98.28 kJ/mol

Step 2:

ΔG = ΔG° + RT ln Q

⇒with Q = the reaction quatient

⇒with T = the temperature = 298 K

⇒with R = 8.314 J / mol*K

⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2 )

⇒ ΔG° = 98.28 kJ/mol - 2* 51.84  kJ/mol

⇒ ΔG° = -5.4 kJ/mol

Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

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Calculating molarity using solute moles A chemist prepares a solution of sodium chloride (NaCl) by measuring out 6.89 mol of sod
hram777 [196]

Answer: Concentration of the chemist's sodium chloride solution is 34.4 mol/L.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml

Given : moles of NaCl = 6.89

volume of solution = 200 ml

Putting in the values we get:

Molarity=\frac{6.89\times 1000}{200}=34.4mol/L

Thus the concentration of the chemist's sodium chloride solution is 34.4 mol/L.

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3 years ago
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