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Flura [38]
1 year ago
7

Chlorine and bromine have very similar chemical properties. This is best explained by the fact that both elements:

Chemistry
1 answer:
34kurt1 year ago
7 0

What is the similarity between chlorine and bromine?

Chlorine and bromine have very similar chemical properties and are best explained by the fact that they both belong to the category of halogens.

Similarities shared by halogens:

Chemical elements are represented as periods and groups on a periodic table. Chemical elements with comparable properties make up each category. Halogens are group 17 elements that are primarily non-metallic.

In the case of halogens, each element's atom possesses seven valence electrons, ns^{2} np^{5}, in which n stands for the energy level. The electron configuration of chlorine is [Ne]3s^{2} 3p^{5}, and the electron configuration of bromine is [Ar]3d^{10}4s^{2} 4p^{5}.

Because of comparable electron configurations, elements of the same group have similar properties. The number of valence electrons, which are located in the outermost (highest energy) s and p orbitals, is particularly similar.

Learn more about halogens here;

brainly.com/question/4725757

#SPJ4

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It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for
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Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

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Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>

Q = c × m × ΔT

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<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>

<em />

The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

\frac{25.35J}{mol.\° C} .\frac{mol}{107.87g} =0.2350J/g.\° C

Q = c × m × ΔT

Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J

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