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miskamm [114]
3 years ago
8

I have no clue what to do, HELP!!

Chemistry
1 answer:
Mashcka [7]3 years ago
3 0
The molar ratios in the reaction are 1:1::1:2, so one Mole (Na2CrO4, produces two moles, (NaNO3).

Using the equation: moles = mass(g) /Mr
1. Calculate the Mr of Na2CrO4
from the periodic table,
Na x 2 = 23 x 2 = 46
Cr x 1 = 52 x 1 = 52
O x 4 = 16 x 4 = 64
46 + 52 + 64 = 162.
moles (na2CrO4) = 253 g / 162 = 1.56 moles.
moles(NaNO3) = 1.56 x 2 = 3.12 moles.

The answer is 3.12 moles.

Hope this helps!
Correct me if I'm wrong.
(Some of this was due to help from Yahoo!)
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7 0
3 years ago
What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?
notsponge [240]
The  empirical formula  for a compound   is KClO3

     Explanation 
 
find  the  moles of each  element
moles  = % composition/molar  mass

molar  mass of  of  potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles  of potassium  =  31.9 / 39 = 0.818  moles
moles of  chlorine    = 28.9/35.5 = 0.814 moles
moles of   oxygen  =  39.2/  16 =  2.45  moles


find the  mole ratio  by  dividing   with  the smallest  mole = 0.814  moles

potassium = 0.818/0.814  =1  
chlorine  =  0.814/0.814 = 1
oxygen =  2.45 /0.814 =3 


the empirical  formula   is therefore = KClO3
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Answer:

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