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FrozenT [24]
2 years ago
10

A boat is 400 feet away from one dock and 500 feet away from the another dock. the angle between the paths is 45°. what is the a

pproximate distance between the docks?
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
8 0

Answer:

  • The approximate distance between the docks is 357 feet

Step-by-step explanation:

Let the distance between docks be d.

This is the opposite side to 45° angle of triangle with other sides 400 ft and 500 ft.

Use the law of cosines to find the value of d:

  • d = \sqrt{400^2+500^2-2*400*500*cos45} =357 (rounded)
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LenaWriter [7]

the 2 equations given are vertical angles which mean they would equal the same.

Set the two equations to equal each other to solve for x:

6(x-2) = 3x+30

Simplify the left side:

6x-12 = 3x+30

Add 12 to eac side:

6x = 3x+42

Subtract 3x from each side"

3x = 42

Divide both sides by 3:

X = 42/3

X = 14


Now you know X, replace x with 14 in the equation for DHG:

DHG = 6(x-2)

6(14-2)

Simplify:

6(12)

Multiply:

72

Angle DHG is 72 degrees.

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3 years ago
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Given that <span>In a canoe race, team a is traveling 6 miles per hour and is 2 miles ahead of team b.

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Answer:

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