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ss7ja [257]
2 years ago
9

f(x)=x^2-x-1 , average rate of change of f over interval -2 greater than or equal to x less than or equal to 1

Mathematics
1 answer:
SCORPION-xisa [38]2 years ago
3 0

The average rate of change within the function f(x)=x^{2} -x-1is -2.

Given The function f(x)=x^{2} -x-1

We have to search out the typical rate of change of function within the interval (-2,1).Interval is largely a variety between numbers lying on the quantity line which may be a line on which different numbers are plotted.

We know that average rate of change =f(b)-f(a)/(b-a)

we have to first know the values of function at different values of x.

f(x)=x^{2} -x-1

f(1)=1-1-1

=-1

f(-2)=4+2-1

=5

b=-2

a=1

put within the formula:

A=-1-5/1+2

=-6/3

=-2

Hence average rate of change of the function within the interval (-2,1) is -2.

Learn more about average at brainly.com/question/20118982

#SPJ10

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sineoko [7]

Answer:

Height of second Bungee jump is 150 feet.

Step-by-step explanation:

Let the height of second jump be x

Now By given details;

Height of first Bungee jump = 200 feet

Also,

first bungee jump is 50 feet higher than your second jump.

Hence,

Height of first jump = 50 + height of second jump

Substituting the values we get;

200=50+x\\x=200-50\\x= 150 ft

Hence the Height of second Bungee jump is 150 feet.

6 0
3 years ago
[WILL GIVE BRANLIEST] Which equation represents circle W?
Margaret [11]

Answer:

ß7wtlirwyeikey.4lifwt7e5lu8-)B-)8-)O_o(+_+)(*_*):-[>.<:-|:-(:-(B-);-):-D:-[(^^):-|:‑X8-):-)

6 0
3 years ago
Read 2 more answers
The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where
Reil [10]

Answer:

The rock will reach to the canyon floor in 3.99 seconds.

Step-by-step explanation:

The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation

h=-16t^2+255

Where, h0 is the initial height of the object.

It can be written as

h=-16t^2+0t+255

The height of the object is zero if it will reach to the canyon floor.

0=-16t^2+0t+255

Quadratic formula:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here a=-16, b=0 and c=255.

t=\frac{-0\pm \sqrt{0^2-4(-16)(255)}}{2(-16)}

t=\frac{\pm \sqrt{16320}}{-32}

t=\pm 3.99

Time cannot be negative, therefore the rock will reach to the canyon floor in 3.99 seconds.

3 0
3 years ago
Read 2 more answers
What is the value of x2/y4 when x = 8 and y = 2​
zaharov [31]

Answer:

The answer is 32.

Step-by-step explanation:

You just fill it the blanks.

(8)2/(2)4 ...

and plug it into a calculator. Hope that helps

6 0
3 years ago
A circular plate is being heated. Its radius is increasing at the rate of 0.02 in/min. At what rate is the area of the plate inc
Evgen [1.6K]

Answer:

\frac{dA}{dr} =2\pi (6in) (0.02 \frac{in}{min})=0.754 \frac{in^2}{min}

Step-by-step explanation:

Data given

\frac{dr}{dt}= 0.02 \frac{in}{min}

r = 6 in

Solution to the problem

We know that the area for a circle is given by:

A= \pi r^2

We want to find at what rate is the area of the plate increasing at the instant when the radius is 6 inches. So we need to take partial derivates in both sides of the equation for the area, and if we do this we got:

\frac{dA}{dr} = 2\pi r \frac{dr}{dt}

Since we have all the values provided we just need to replace and we got:

\frac{dA}{dr} =2\pi (6in) (0.02 \frac{in}{min})=0.754 \frac{in^2}{min}

5 0
3 years ago
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