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ss7ja [257]
1 year ago
9

f(x)=x^2-x-1 , average rate of change of f over interval -2 greater than or equal to x less than or equal to 1

Mathematics
1 answer:
SCORPION-xisa [38]1 year ago
3 0

The average rate of change within the function f(x)=x^{2} -x-1is -2.

Given The function f(x)=x^{2} -x-1

We have to search out the typical rate of change of function within the interval (-2,1).Interval is largely a variety between numbers lying on the quantity line which may be a line on which different numbers are plotted.

We know that average rate of change =f(b)-f(a)/(b-a)

we have to first know the values of function at different values of x.

f(x)=x^{2} -x-1

f(1)=1-1-1

=-1

f(-2)=4+2-1

=5

b=-2

a=1

put within the formula:

A=-1-5/1+2

=-6/3

=-2

Hence average rate of change of the function within the interval (-2,1) is -2.

Learn more about average at brainly.com/question/20118982

#SPJ10

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6 0
2 years ago
Just need the answer for a and b
34kurt

Answer:

2⁵× 2ˣ = 256

x= 3

(1/3)² (1/3)ˣ = 1/729

x= 4

Step-by-step explanation:

2⁵× 2ˣ = 256

x= 3

use Product Rule: xᵃxᵇ=xᵃ⁺ᵇ

convert both sides to the same base.

2⁵⁺ˣ = 2⁸

cancel the base of 2 on both sides.

5+x=8

subtract 5 from both sides.

x=8-5

simplify  8-5 3.

x=3

(1/2)² (1/3)ˣ = 1/729

x = 4

use division distributive property: (x/y)ᵃ=xᵃ/yᵃ

i hope this helped i didn't feel like typing the rest out though lol  :(

5 0
2 years ago
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