Answer:
1.F: About 6*10^14 Hz
2.E: About 4*10^ -19 J
Explanation:
Frequency: We knew that the speed of a wave is its wavelength(λ)* frequency(f, in Hz). By the wave-particle duality we know we can calculate the frequency of light in the same way. So, c=495nm *f, f=c/495nm=> (299,792,458 m/s) / (4.95*10^-7 m)
=6.05*10^14 /s
Energy: The energy photon contains can be calculate by this formula-- E=hf
f is the frequency and h is Planck's constant which is about 6.62 ×10^-34 *m^2*kg/s (after dimensional analysis ) =6.62*10^ -34 J*s.
So, the energy of a blue photon is (6.05*10^14)*(6.62*10^-34)=40.051*10^-20= 4.051*10^-19 J
Energy can change form, but the total amount of energy stays the same.
Write a:
● Hypothesis
●Procedures
●Materials
●Data Table
●Conclusion
●Variables (Independent and dependent)
●Bibliography
Answer:
Explanation:
From the question we are told that
The electric filed is 
Generally according to Gauss law
=> 
Given that the electric field is pointing downward , the equation become
Here 
is the excess charge on the surface of the earth
is the surface area of the of the earth which is mathematically represented as
Where r is the radius of the earth which has a value 
substituting values
So
Here 
s the permitivity of free space with value
substituting values
