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Gre4nikov [31]
3 years ago
9

Add these measurements, using significant digit rules:

Physics
1 answer:
tia_tia [17]3 years ago
3 0

Here we have to add the two measurements given in the question

The measurement values are given as 1.0090 cm and 0.02 cm.we have to  add them on the basis of significant figure rules.

As per the addition rule in terms of significant figures

1-First we have to select the number of significant digits after the decimal point of each quantity.

2-Now we have to remember that during the addition ,the resultant of two quantities will follow the quantity having least number of significant figures after the decimal point.

3-Here we are considering the minimum number of significant figures after the decimal points not the minimum number of significant figures in case of multiplication and division

Now we have to add these two quantities as per the above rule-

         1.0090 cm +0.02 cm

         =1.0290 cm

Here the result  will follow 0.02 which has minimum number of significant figures after the decimal points.

Hence we have to round off the number from 9 of 1.0290

As 9 is  greater than 5 ,so he actual result will be 1.03 cm

       

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A ball of mass 0.220 kg that is moving with a speed of 6.3 m/s collides head-on and elastically with another ball initially at r
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Answer:

(a) Velocity of target is 2.7 m/s.

(b) Mass of target is 0.807 kg.

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Mass of ball m_{1}=0.22\;kg

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Final speed of the ball v_{2f}=-3.6\;m/s

Part (a) The second ball is initially at rest. So, by the conservation of momentum,

p_{i}=p_{f}\\m_{1}v_{1i}+m_{2}v_{2i}=m_{1}v_{1f}+m_{2}v_{2f}\\0.22\times6.3+m_{2}\times 0=0.22\times(-3.6)+m_2v_{2f}\\m_2v_{2f}=2.178\:\:\:\:\;\;\;\;\;\;\;\;\;\;    ...(1)

Now, the velocity of approach is equal to the velocity of separation,

v_{1i}-v_{2i}=v_{2f}-v_{1f}\\6.3-0=v_{2f}-(-3.6)\\v_{2f}=2.7\;m/s

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5 0
3 years ago
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b) B = 2.38\times10^{-5} \hat i

Explanation:

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B= \frac{\mu_o}{4\pi}\frac{q (\vec v\times \hat r)}{r^2}

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Because \hat j \times \hat i = -\hat k,

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b) The velocity vector is in +y direction and the point is on z-axis

Because \hat j \times \hat k = \hat i,

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B= 1\times 10^{-7}\times 7\times 10^{-6}\times \frac{8.50\times 10^6 \hat j\times \hat k}{0.500^2}\\B = 2.38\times10^{-5} \hat i

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 65.769230769231 is the answer to  <span>A motorcycle travels 836 meters in 19 seconds. What is its average speed?</span>
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