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Korvikt [17]
4 years ago
15

Please help, answers are 5m -1m 4m 9m

Physics
2 answers:
Anvisha [2.4K]4 years ago
6 0

Answer:

-1

Explanation:

dude easey

Tcecarenko [31]4 years ago
3 0

Answer: The answer is -1m. Hope this helps :)

Explanation:

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A 600 g model rocket is on a cart that is rolling to the right at a speed of 4.0 m/s. The rocket engine, when it is fired, exert
murzikaleks [220]

Answer:

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

Explanation:

Step 1: Data given

mass of the rocket = 600 grams

speed = 4.0 m/s

Step 2: Calculate weight

Fw = mg

with Fw = the weight (in Newton)

with m = the mass (in kg)

with g = the acceleration due to gravity (9.81 m/s²).

Fw = (0.600 kg)(9.81 m/s²)  = 5.886 N

Step 3: Calculate force available to provide acceleration

The rocket engine, when it is fired, exerts a 8.0 AND vertical thrust on the rocket.

5.886 N of that force will be used to counter the rocket's weight, leaving 2.114 N of force available to provide acceleration.  

Step 4: Calculate the rocket's upward acceleration:

Fnet = m*a

With Fnet = the net force (the force that remains after the rocket's weight is compensated)

with a = the rocket's acceleration (in m/s²)

2.114 N = (0.600 kg)*a

a = 3.52 m/s²  = the rocket's upward acceleration

Step 5: Calculate how long it will take to rise 20 meters into the air.

Δy = v0*t + 1/2 at²

with v0 = 0m/s

Δy = 1/2 at²

20 m = 1/2(3.52)t²

20 m = (1.76 m/s²)t²

11.36 = t²

t = 3.37 s

This means the rocket will take 3.37 seconds to reach the hoop.  It should be launched when the cart is 3.37 seconds away from being directly beneath the hoop.  

Step 6: Calculate the distance

v = Δx / t

4.0 m/s = Δx / 3.37 s

Δx = 13.48 m

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

8 0
4 years ago
At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant
Blizzard [7]
(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then 
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

--------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
3 years ago
Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the
Reptile [31]
I don't know what the tables you have look like but her <span>displacement</span> would be -1m

4 0
3 years ago
Read 2 more answers
As the size of the nucleus increases, more______are needed to maintain the attractive force.
Neko [114]
The attractive force that keeps the nucleus together is called nucleus force.
<span>The nucleus becomes increasingly more stable upon the addition of nucleons up to iron-56.
</span>So, as the size of the nucleus increase more iron 56 are needed.
Iron-56<span> (</span><span>56Fe</span><span>) is the most common isotope of </span><span>iron.</span>
6 0
3 years ago
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At which point does a substance have the greatest amount of kinetic energy
kogti [31]
The hottest temp i think
8 0
3 years ago
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